Answer by Tryss for Does it have a valid mathematical meaning?
It means by definition that it's equal to $2^{a_m\log(m)}$, with $a_m$ a bounded sequence.In other world, there exists $C$ such that $0 \leq 2^{O(\log(m))} \leq 2^{C\log(m)}$Also, notice that...
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Does the following expression:$$2^{O(\log m)}$$have any mathematical meaning? Is it even correct to write this? I have certain doubts.$O(\log m)$ is not a well-defined number, so it's difficult to say...
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